(2х-5)²-(2х-3)(2х+3)=0 (3х+5)(3х--1)²=10 2(2х+1)²-8(х+1)(х-1)=34 - вопрос №2523230353110221811344835241 от bi2002 27.06.2021 15:17

Question

Алгебра: (2х-5)²-(2х-3)(2х+3)=0 (3х+5)(3х--1)²=10 2(2х+1)²-8(х+1)(х-1)=34

bi2002 · Answer

(2x-5)²-4x²+9=4x²+25-20x-4x²+9=34-20x34-20x=020x=34x=1.79x²-25-(3x-1)²=9x²-25-9x²-1+6x=6x-256x-25=106x=35x=5.5/62(2x+1)²-8(x²-1)=8x²+2+8x-8x²+8=8x+108x+10=348x=24x=3...