1. log32 64 2. log10 100 в корне 1000 3. 13 log5 - вопрос №13264210100100031351325434514731 от svetacok 27.01.2022 04:29

Question

Алгебра: 1. log32 64 2. log10 100 в корне 1000 3. 13 log5 13вкорне25 4. 3/5 log2 1/8 5. log8 log4 16 6. log16 log12 144+2/5 log2 32 умоляю

svetacok · Answer

Lg(100*√1000)=lg(10²*10³/²)=lg10⁷/²=3,513*log₅13*√25=13*log₅13*5=13(log₅13-log₅5)=13(log₅13-1)(3/5)*log₂(1/8)=(3/5)*log₂2⁻³=-9/5=-1,8log₈(log₄16)=log₈(log₄4²)=log₈2=log₂³2=1/2³=1/8log₁₆(log₁₂144)+(2/5)*log₂32=log₁₆(log₁₂12²)+(2/5)log₂2⁵=log₂⁴2+0,4*5=1/4+2=2,25....